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gander123
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Hey
QPS00253 GMAT Prep Pack 1
"For a certain set of numbers, if x is in the set, then x-3 is also in the set. If the number 1 is in the set, which of the following must also be in the set?
I. 4
II. -1
III. -5
OA: C
OA explanation:
"The rule for set membership is: If x is in the set, then x-3 is also in the set. It is given that 1 is in the set. Therefore, 1-3 = -2 is in the set. Also, since -2 is now known to be in the set, -2-3 = -5 is also known to be in the set. Similarly, since -5 is now known to be in the set, -8 is also known to be in the set. Note that the set could be {1,-2,-5,-8,...} and this does not contain either 4 or -1. Therefore, it is not true that either 4 or -1 must be in the set. Only -5 must be in the set."
My question:
I initally set x=1 and consequently x-3= - 2 then -5 is in the set and so forth.
BUT, I also set x-3 = 1 through which I obtained 4 is in the set.
Am I right in assuming that we do not necessarily have to set x-3 = 1 to obtain 4 is in the set, because the question stem asked us
So setting x-3 = 1 is a "COULD BE TRUE" value but not a "MUST BE TRUE" value?
Appreciate your feedback..
Cheers, Tobi
QPS00253 GMAT Prep Pack 1
"For a certain set of numbers, if x is in the set, then x-3 is also in the set. If the number 1 is in the set, which of the following must also be in the set?
I. 4
II. -1
III. -5
OA: C
OA explanation:
"The rule for set membership is: If x is in the set, then x-3 is also in the set. It is given that 1 is in the set. Therefore, 1-3 = -2 is in the set. Also, since -2 is now known to be in the set, -2-3 = -5 is also known to be in the set. Similarly, since -5 is now known to be in the set, -8 is also known to be in the set. Note that the set could be {1,-2,-5,-8,...} and this does not contain either 4 or -1. Therefore, it is not true that either 4 or -1 must be in the set. Only -5 must be in the set."
My question:
I initally set x=1 and consequently x-3= - 2 then -5 is in the set and so forth.
BUT, I also set x-3 = 1 through which I obtained 4 is in the set.
Am I right in assuming that we do not necessarily have to set x-3 = 1 to obtain 4 is in the set, because the question stem asked us
?which of the following must also be in the set?
So setting x-3 = 1 is a "COULD BE TRUE" value but not a "MUST BE TRUE" value?
Appreciate your feedback..
Cheers, Tobi


















