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GMAT Prep Test 1 q16 - Please Help

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by OneMoreTime » Wed Feb 13, 2008 6:56 pm
I apologize if this exists in another thread but I did search and was unable to find it.

The following problem is really giving me a hard way to go. Can someone please explain it?

The total price of a basic computer and a printer was $2500. If the same printer had been purchased with an enhanced computer whose price was $500 more than the price of the basic computer, then the price of the printer would have been 1/5 of that total. What was the price of the basic computer?

a)$1500
b)$1600
c)$1750
d)$1900
e)$2000

The answer is 'D' but again I'm not sure how this was gotten.

Thanks in Advanced!
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math translation

by resilient » Wed Feb 13, 2008 7:55 pm
the solution starts out with a = computer and b = printer. this gets our variables straight.

the statement gives the solution of printer and computer = 2500.

so a+b=500. the new computer and printer solution is a+500= ??????? from here I am lost. I am very curious how to solve this out!
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Re: GMAT Prep Test 1 q16 - Please Help

by Stuart@KaplanGMAT » Wed Feb 13, 2008 11:10 pm
OneMoreTime wrote:I apologize if this exists in another thread but I did search and was unable to find it.

The following problem is really giving me a hard way to go. Can someone please explain it?

The total price of a basic computer and a printer was $2500. If the same printer had been purchased with an enhanced computer whose price was $500 more than the price of the basic computer, then the price of the printer would have been 1/5 of that total. What was the price of the basic computer?

a)$1500
b)$1600
c)$1750
d)$1900
e)$2000

The answer is 'D' but again I'm not sure how this was gotten.

Thanks in Advanced!
We're told that if we spent an extra $500, the price of the printer would be 1/5 of the total.

We originally spent $2500, so with the extra $500 our new cost is $3000.

We know that the printer costs 1/5(3000) = 600.

Our original cost was $2500, so if we subtract the $600 for the printer, that means that the computer cost us $1900: choose (d).
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by davidforsberg » Thu Feb 14, 2008 7:09 am
I did it the long way around and also came up with the correct answer:

C+P=2500 (1st equation)

(C+500)+((C+500+P)/5)=C+500+P (2nd equation)

If you work them out you get P=600 and C=1900
T minus 17 hours
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by xilef » Thu Feb 14, 2008 5:36 pm
p+c=2500
p+(c+500)=5p (since printer is 1/5 of the total)

solve for p and c - 600 and 1900
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RE:

by OneMoreTime » Sat Feb 16, 2008 11:33 am
Thanks all for the help! :D
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