BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

the company operates in its factory

This topic has expert replies
Post new topic Post Reply
Previous Topic Next Topic
User avatar
GMAT Instructor
Posts: 3650
Joined: Wed Jan 21, 2009 4:27 am
Location: India
Thanked: 267 times
Followed by:80 members
GMAT Score:760

the company operates in its factory

by sanju09 » Sat Aug 14, 2010 2:15 am
In a certain company, the formula for maximizing profits is P = -25 ×^2 + 7500 x, where P is profit and x is the number of machines the company operates in its factory. What value for x will maximize P?
(A) 10
(B) 50
(C) 150
(D) 200
(E) 300


[spoiler]Source: gmatclub.com[/spoiler]
The mind is everything. What you think you become. -Lord Buddha



Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001

www.manyagroup.com
Top
Source: — Problem Solving |
User avatar
Legendary Member
Posts: 1460
Joined: Tue Dec 29, 2009 1:28 am
Thanked: 135 times
Followed by:7 members

by selango » Sat Aug 14, 2010 2:50 am
-25 X^2 + 7500 x

P=7500x-25x^2

P=25x(300-x)

x=150

P=25*150*150

P is maximum when x is 150

Pick C
--Anand--
Top
Senior | Next Rank: 100 Posts
Posts: 32
Joined: Sun Aug 15, 2010 7:33 am
Thanked: 1 times

by thirst4edu » Tue Aug 17, 2010 11:00 am
selango wrote:-25 X^2 + 7500 x

P=7500x-25x^2

P=25x(300-x)

x=150

P=25*150*150

P is maximum when x is 150

Pick C
Can you please explain, how you came up with 150 ?
Even after this P=25x(300-x), I am unable to visualize which number to try first.

Thanks in advance!
"Learning never exhausts the mind."
--Leonardo da Vinci
Top
Legendary Member
Posts: 2326
Joined: Mon Jul 28, 2008 3:54 am
Thanked: 173 times
Followed by:2 members
GMAT Score:710

by gmatmachoman » Tue Aug 17, 2010 12:10 pm
For maxmia /minima conditions we can use second order differentiation methods:

dp/dx = -50x + 7500 ; equate to zero to get value of x

50x = 7500

x = 150

To check x will give max value , try to do second order differentiation of p; it should give d^2P/dx^2 <0



d^2P/dx^2 = -50 which is less than zero

pick X= 150
Top
Senior | Next Rank: 100 Posts
Posts: 32
Joined: Sun Aug 15, 2010 7:33 am
Thanked: 1 times

by thirst4edu » Tue Aug 17, 2010 12:19 pm
gmatmachoman wrote:For maxmia /minima conditions we can use second order differentiation methods:

dp/dx = -50x + 7500 ; equate to zero to get value of x

50x = 7500

x = 150

To check x will give max value , try to do second order differentiation of p; it should give d^2P/dx^2 <0



d^2P/dx^2 = -50 which is less than zero

pick X= 150
Wow!! Its been more than 10 yrs, I forgot derivatives.. is derivative of x^2 , 2x?
And is there any simpler method? I am sure GMAT doesnt want to test us on differential equations. Excellent approach though, no offence on your approach.

Thanks!
"Learning never exhausts the mind."
--Leonardo da Vinci
Top
Legendary Member
Posts: 2326
Joined: Mon Jul 28, 2008 3:54 am
Thanked: 173 times
Followed by:2 members
GMAT Score:710

by gmatmachoman » Tue Aug 17, 2010 12:29 pm
In that case , u need to start plug in numbers which is really time consuming...

Since i work with derivatives day in day out....its a part of me these days..LOL
Top
User avatar
GMAT Instructor
Posts: 3650
Joined: Wed Jan 21, 2009 4:27 am
Location: India
Thanked: 267 times
Followed by:80 members
GMAT Score:760

by sanju09 » Wed Aug 18, 2010 2:12 am
thirst4edu wrote:
gmatmachoman wrote:For maxmia /minima conditions we can use second order differentiation methods:

dp/dx = -50x + 7500 ; equate to zero to get value of x

50x = 7500

x = 150

To check x will give max value , try to do second order differentiation of p; it should give d^2P/dx^2 <0



d^2P/dx^2 = -50 which is less than zero

pick X= 150
Wow!! Its been more than 10 yrs, I forgot derivatives.. is derivative of x^2 , 2x?
And is there any simpler method? I am sure GMAT doesnt want to test us on differential equations. Excellent approach though, no offence on your approach.

Thanks!
Since P = -25 X^2 + 7500 x = 25 x (300 - x); and in order to maximise P, we need to maximise the product of the two unknowns x and 300 - x, which is maximum when x = 300 - x or at [spoiler]x = 150[/spoiler], P is maximum.

Learn this very important property of two positive numbers a and b, that their product is maximum when a = b.

[spoiler]C[/spoiler]

Differential Calculus techniques are not tested on GMAT, Govind! Please do not offer minors, your toys.
The mind is everything. What you think you become. -Lord Buddha



Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001

www.manyagroup.com
Top
Senior | Next Rank: 100 Posts
Posts: 32
Joined: Sun Aug 15, 2010 7:33 am
Thanked: 1 times

by thirst4edu » Wed Aug 18, 2010 6:33 am
sanju09 wrote: Learn this very important property of two positive numbers a and b, that their product is maximum when a = b.
Thanks Sanju!! Yesterday, I did come close to equation 25x(300-x), and thought there has to be something to do with balancing between x & (300 - x).. but was not sure. Your statement explains it all! :)

Thank You!!
"Learning never exhausts the mind."
--Leonardo da Vinci
Top
User avatar
GMAT Instructor
Posts: 3650
Joined: Wed Jan 21, 2009 4:27 am
Location: India
Thanked: 267 times
Followed by:80 members
GMAT Score:760

by sanju09 » Mon Aug 23, 2010 2:30 am
thirst4edu wrote:
sanju09 wrote: Learn this very important property of two positive numbers a and b, that their product is maximum when a = b.
Thanks Sanju!! Yesterday, I did come close to equation 25x(300-x), and thought there has to be something to do with balancing between x & (300 - x).. but was not sure. Your statement explains it all! :)

Thank You!!
Thanks thirst4edu, actually my definition about the rule is not in its full, it in fact says that if the sum of two positive numbers is constant, their product is maximum when the numbers are equal.
The mind is everything. What you think you become. -Lord Buddha



Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001

www.manyagroup.com
Top
Post new topic Post Reply
• Page 1 of 1