Cant seem to get this really easy one.
1> Group of 10 members. 4 French and the rest are Spanish/German. How many ways to choose a 3 member committee, with atleast one French..
My approach (which is wrong Im guessing since it doesnt come up with the OA)
3 spots available, 1 reserved for the French others open to all.
So 4C1 * 9C2
Aother approach (which gives the right answer)
Total combinations are 10C3
Number of ways of selecting NO french = 6C3
Atleast one French = 10C3 - 6C3.
Whats wrong with approach 1 ?
Thanks
1> Group of 10 members. 4 French and the rest are Spanish/German. How many ways to choose a 3 member committee, with atleast one French..
My approach (which is wrong Im guessing since it doesnt come up with the OA)
3 spots available, 1 reserved for the French others open to all.
So 4C1 * 9C2
Aother approach (which gives the right answer)
Total combinations are 10C3
Number of ways of selecting NO french = 6C3
Atleast one French = 10C3 - 6C3.
Whats wrong with approach 1 ?
Thanks
















