BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

GMAT prep software question

This topic has expert replies
Post new topic Post Reply
Previous Topic Next Topic
Source: — Problem Solving |
User avatar
Community Manager
Posts: 789
Joined: Sun Jan 28, 2007 3:51 pm
Location: Silicon valley, California
Thanked: 30 times
Followed by:1 members

Re: GMAT prep software question

by jayhawk2001 » Sat May 12, 2007 6:43 pm
atarafder wrote:A equilateral traingle inscribed in circle divides it into 3 equal arcs. So total circumference = 32.
2pir = 32
2r = 10.19 appx to 11 = diiameter.

So the answer is 11. Is my reasoning correct?
How did you get circumference to be 32 ?

Arc ABC covers 2/3 of the circle.

2/3 * 2*pi*r = 24

Solve for 2r and you'll get 11
Top
Junior | Next Rank: 30 Posts
Posts: 17
Joined: Sat May 12, 2007 11:11 am

by atarafder » Sat May 12, 2007 6:55 pm
my bad, I meant 36 and not 32. In a hurry, I calculated 24/2 as 8 and not 12.
Top
Post new topic Post Reply
• Page 1 of 1