- Neha Mittal
- Newbie | Next Rank: 10 Posts
- Posts: 2
- Joined: Tue Jul 24, 2007 2:44 am
(x+2) = +/- 2(x-2)
Case 1
x+2 = 2x-4
x=6.
Case 2
x+2=-2x+4
3x=2
x=2/3.
Edited..
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X = 2/3 and 6 for two different cases.Neha Mittal wrote:|x+2| = 2|x-2| find range of x
I do not understand why x = 6 is an invalid solution
Just as a side-note, there is no "range" here as [2/3,6) would mean that values of X from (and including) 2/3 all the way up to 6 would satisfy this expression, and that is not the case (just check x=1 for example).n@resh wrote:X = 2/3 and 6 for two different cases.Neha Mittal wrote:|x+2| = 2|x-2| find range of x
I do not understand why x = 6 is an invalid solution
so range will be : [2/3, 6)
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