ration to x :(y+z)= 12/15*18/(15+18)
=12*11/90
=22/15
og math # 130
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- bpdulog
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I fell for the trap answer C.
Can it be fair to say that every time we are given a time problem and solve for the rate, all we have to do is take the inverse?
Can it be fair to say that every time we are given a time problem and solve for the rate, all we have to do is take the inverse?
NO EXCUSES
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x does 1/12 of the job in 1 hour.
y 1/15
z 1/18
y + z = (1/15) + (1/18) = (33/270)
x/(y + z) = (1/12)/(33/270) = 15/22
These are the rates, so the time is in the ratio 22/15.
Common-sense check: 33/270 > 1/12, so y + z is faster than x, so x must take more time!
y 1/15
z 1/18
y + z = (1/15) + (1/18) = (33/270)
x/(y + z) = (1/12)/(33/270) = 15/22
These are the rates, so the time is in the ratio 22/15.
Common-sense check: 33/270 > 1/12, so y + z is faster than x, so x must take more time!
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- ronnie1985
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Quite easy.
Speed X = 1/12 hr^-1
Y+Z = 1/15+1/18 hr^-1 = 11/90 hr^-1
Ratio = 12 / (90/11) = 22/15
(D) is answer.
Speed X = 1/12 hr^-1
Y+Z = 1/15+1/18 hr^-1 = 11/90 hr^-1
Ratio = 12 / (90/11) = 22/15
(D) is answer.
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IMO : D
Required: Time spent by X/Time spent by Y and Z
Time spent by X =12
Time spent by Y and Z = 1/(1/y+1/z)= 90/11
Ans: 12/(90/11)= 22/15
Required: Time spent by X/Time spent by Y and Z
Time spent by X =12
Time spent by Y and Z = 1/(1/y+1/z)= 90/11
Ans: 12/(90/11)= 22/15
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working alone, printers x,y, and z can do a certain printing job, consisitning of a large number of pages, 12, 15, and 18 hours, respectively. What is the ratio of the time it takes printer x to do the job, working at its rate, to time it takes printers y and z to do the job, working together at their individual rates?
a. 4/11
b.1/2
c. 15/22
d.22/15
e.11/4
Tx=12, Ty=15 & Tz=18
Tyz=Ty*Tz/(Ty+Tz)
Tyz=15*18/33
Tx/Tyz=12*33/15*18
Tx/Tyz=22/15
Hence, Option D is correct
a. 4/11
b.1/2
c. 15/22
d.22/15
e.11/4
Tx=12, Ty=15 & Tz=18
Tyz=Ty*Tz/(Ty+Tz)
Tyz=15*18/33
Tx/Tyz=12*33/15*18
Tx/Tyz=22/15
Hence, Option D is correct
working alone, printers x,y, and z can do a certain printing job, consisitning of a large number of pages, 12, 15, and 18 hours, respectively. What is the ratio of the time it takes printer x to do the job, working at its rate, to time it takes printers y and z to do the job, working together at their individual rates?
a. 4/11
b.1/2
c. 15/22
d.22/15
e.11/4
solution:
we have to find x : y+z
therefore
1/12 : 1/15 + 1/18
1/12 : 6 + 5 / 90
1/12 : 11 / 90
90 / 12 * 11
we get
15 / 22
now just receprocal it
22 / 15
D is the right choice
a. 4/11
b.1/2
c. 15/22
d.22/15
e.11/4
solution:
we have to find x : y+z
therefore
1/12 : 1/15 + 1/18
1/12 : 6 + 5 / 90
1/12 : 11 / 90
90 / 12 * 11
we get
15 / 22
now just receprocal it
22 / 15
D is the right choice
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x takes 12 hrs to complete a job
when y and z work together -
rate of working for y is 1/15
rate of working for z = 1/18
when both y and z work together- rate is 1/y+1/z = 1/15+1/18 = 11/90
hence y and z together can complete the task in 90/11 hrs
ratio of x :(y and z)=12/(90/11) = 12 * 11/90 = 22/15.
when y and z work together -
rate of working for y is 1/15
rate of working for z = 1/18
when both y and z work together- rate is 1/y+1/z = 1/15+1/18 = 11/90
hence y and z together can complete the task in 90/11 hrs
ratio of x :(y and z)=12/(90/11) = 12 * 11/90 = 22/15.
X's rate: 1/12
Y's rate: 1/15
Z's rate: 1/18
Find ratio of X's rate to Y+Z's rate
Y+Z's rate:
1/15 + 1/18 ==> 18/270 + 15/270 ==> 33/270 ==> 11/90
11/90 = Y+Z's amount of job done in 1 hour, therefore 90/11 = hours to complete one job
Now find ratio of X to Y+Z
12/(90/11) ==> (12*11)/90 ==> 132/90 ==> 66/45 ==> 22/15
answer is D, 22/15
Y's rate: 1/15
Z's rate: 1/18
Find ratio of X's rate to Y+Z's rate
Y+Z's rate:
1/15 + 1/18 ==> 18/270 + 15/270 ==> 33/270 ==> 11/90
11/90 = Y+Z's amount of job done in 1 hour, therefore 90/11 = hours to complete one job
Now find ratio of X to Y+Z
12/(90/11) ==> (12*11)/90 ==> 132/90 ==> 66/45 ==> 22/15
answer is D, 22/15