og math # 130
BTW --work problems are just one of those you should know the formula to solving for time (TIME A * TIME B divided by TIME A + TIME B) when given discrete simultaneous rates. Read up on this because it will save you a bunch of time from trying to figure out what the heck will be going on with which rate etc. It's kinda like triangle problems. You will eventually solve them but you really should not be inventing the wheel during the test. I think the GMAT just wants you to be able to recognize which type of problem you are working with and apply very simple mathematics.
D 22/15
X does 1/12th of work in an hour.
Y+Z together do 1/18 and 1/15 of work together in an hour.
Simplifying they both together do 11/90 th of work.
Therefore they will complete the work in 90/11 if they work together
now the ratio asked is (12*11)/90---->22/15
X does 1/12th of work in an hour.
Y+Z together do 1/18 and 1/15 of work together in an hour.
Simplifying they both together do 11/90 th of work.
Therefore they will complete the work in 90/11 if they work together
now the ratio asked is (12*11)/90---->22/15
- Deependra1
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- way2ashish
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Work done by x in 1 hour = 1/12
Work done by y and z in 1 hour = 1/15+1/18=11/90
so total time taken by both to complete the job =90/11 hrs
time taken by x /time taken by a & b = 18/(90/11)=22/15
Work done by y and z in 1 hour = 1/15+1/18=11/90
so total time taken by both to complete the job =90/11 hrs
time taken by x /time taken by a & b = 18/(90/11)=22/15
resilient wrote:working alone, printers x,y, and z can do a certain printing job, consisitning of a large number of pages, 12, 15, and 18 hours, respectively. What is the ratio of the time it takes printer x to do the job, working at its rate, to time it takes printers y and z to do the job, working together at their individual rates?
a. 4/11
b.1/2
c. 15/22
d.22/15
e.11/4
qa is d. I dont see why C is wrong. I dont see why the solution flips the combined rate of y and z working together. help stuart?
Best way to save time on such problems is to remove the fraction part by assuming the work as a LCM of the time taken to complete the work and then find individual work done/unit time. This has been explained earlier by Farooq.
Working with numbers definitely saves time when compared to working with fractions
Working with numbers definitely saves time when compared to working with fractions
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Let us say the printer needs to print 180 pages.
Then,
the rate at which printer x works => 180/12 => 15 pages/hr
the rate at which printer y works => 180/15 => 12 pages/hr
the rate at which printer z works => 180/18 => 10 pages/hr
the rate at which printers y and z work => 10+12 => 22 pages/h
ratio of time taken by printer x to printer y and z together => (180/15)/(180/22) => 22/15
Then,
the rate at which printer x works => 180/12 => 15 pages/hr
the rate at which printer y works => 180/15 => 12 pages/hr
the rate at which printer z works => 180/18 => 10 pages/hr
the rate at which printers y and z work => 10+12 => 22 pages/h
ratio of time taken by printer x to printer y and z together => (180/15)/(180/22) => 22/15