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og ds 127

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og ds 127

by resilient » Fri Feb 08, 2008 6:27 pm
s=2/n/1x+2/3x

what is the value of s?


1. x=2n
2. n=1/2


original equation boils down to s=6x/5n

how is statement 1 correct? I put C
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by its_me07 » Mon Feb 11, 2008 12:48 am
Sorry i cant read ur question stem properly but if question boils down to 6x/5n then u can put n=x/2 from statement 1,you can get the value of s as x is cancelled.

Hope this help.
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Re: og ds 127

by RyanDe680 » Mon Feb 11, 2008 9:23 am
Enginpasa1 wrote:s=2/n/1x+2/3x

what is the value of s?


1. x=2n
2. n=1/2


original equation boils down to s=6x/5n

how is statement 1 correct? I put C
Is the original questions (2/n)/x or is it 2/(n/x)? That has a large impact on your answer.
Ryan
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sorry folks

by resilient » Mon Feb 11, 2008 10:44 am
the question is complcated and has multiple layers of fractions. that is as simple as i can put it...but the question is # 127 Data Sufficiency on OG. thank you
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by mollyrg » Mon Feb 11, 2008 11:44 am
DS # 127:

It does simplify as 6x/5n.
By substituting (1) x=2n, n cancels out & u get the value for S. Sufficient
But (2) alone is insufficient.

Hence, ans is A

molly
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by gmatguy16 » Mon Feb 11, 2008 5:38 pm
i guess in that case a is not the answer since both x and n can be 0 which results in s = 0 ,if x and n are non-zero only then we can cancel ,hence answer is c imo.whats oa?
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