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A repunit is a positive integer that contains only the digit

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by BTGmoderatorDC » Fri Aug 23, 2019 3:45 pm

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A repunit is a positive integer that contains only the digit 1. If the integer r is a repunit, is r prime?

(1) The number of digits in r is a multiple of 3.
(2) 0 < r < 1200

OA A

Source: Veritas Prep
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Source: — Data Sufficiency |

by Ian Stewart » Sat Aug 24, 2019 7:28 am
If every digit of r is 1, then the number of digits of r will be equal to the sum of the digits of r. If, as Statement 1 tells us, the number of digits of r is a multiple of 3, then the sum of r's digits is a multiple of 3, and r is divisible by 3. Since r is not equal to 3, r cannot be prime, and Statement 1 is sufficient to give us a 'no' answer to the question.

Statement 2 is not sufficient because r could be 11, which is prime, or 111, which is divisible by 3 and is not prime. So the answer is A.
For online GMAT math tutoring, or to buy my higher-level Quant books and problem sets, contact me at ianstewartgmat at gmail.com

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by Brent@GMATPrepNow » Sat Oct 19, 2019 2:00 pm
BTGmoderatorDC wrote:A repunit is a positive integer that contains only the digit 1. If the integer r is a repunit, is r prime?

(1) The number of digits in r is a multiple of 3.
(2) 0 < r < 1200
Target question: Is r prime?

Given: Integer r is a repunit
So, some possible values of r include: 1, 11, 111, 1111, 111111111111111111, etc

Statement 1: The number of digits in r is a multiple of 3.
So, r could equal 111 or 111,111 or 111,111,111 or 111,111,111,111 etc
We know that, if the sum of the digits in a number is divisible by 3, then that number is also divisible by 3
For example, since the digits in 111 add to 3 (and 3 is divisible by 3), we know that 111 is divisible by 3, which means 111 is NOT prime.
Likewise, since the digits in 111,111 add to 6 (and 6 is divisible by 3), we know that 111,111 is divisible by 3, which means 111,111 is NOT prime.
And, since the digits in 111,111,111 add to 9 (and 9 is divisible by 3), we know that 111,111,111 is divisible by 3, which means 111,111,111 is NOT prime.
As we can see, if the number of digits in r is a multiple of 3, then the sum of r's digits will be divisible by 3.
So, the answer to the target question is NO, r is NOT prime
Since we can answer the target question with certainty, statement 1 is SUFFICIENT

Statement 2: 0 < r < 1200
There are 4 possible values of r: 1 or 11 or 111 or 1111
Case a: If r = 11, then r IS prime
Case b:If r = 111, then r is NOT prime
Since we cannot answer the target question with certainty, statement 2 is NOT SUFFICIENT

Answer: A

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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