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by GmatKiss » Sat Oct 29, 2011 6:59 am
Two triangles are shown: Not drawn to scale. The triangle on the left is smaller, called s. The triangle on the right is larger, called S. The angles are, x, y, and z for both.

Question: If the area of the triangle on the right is twice the area of the triangle on the left, then in terms of s, S=

A) Sq.rt 2/2 *s

B) Sq.rt 3/2 * s

C) Sq.rt 2

D) Sq.rt 3

E) 2s
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by shankar.ashwin » Sat Oct 29, 2011 8:37 am
Without any math here, you know for a given set of angles, you could draw similar triangles in which each side would increase proportionally.

Now since Area(Bigger) = 2Area(Smaller)

Both the base and height in the bigger triangle would have increased proportionally such that their product becomes two times the smaller.
Each would have to increase by Sqrt(2) to produce an area twice the smaller. (Area(small) = 1/2 bh) and (Area(big) = 1/2 * Sqrt(2)b * Sqrt(2)h)

C
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by mankey » Mon Oct 31, 2011 2:16 am
Can some expert please provide an explanation to this one?

Thanks.
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