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Jinglander
- Senior | Next Rank: 100 Posts
- Posts: 58
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Jinglander,
There are solutions available for this equation.Can you post the answer options.
If x and y are integers.
x=6,y=8,6^2+8^2=36+64=100
x+y=14
x=-6,y=-8,(-6)^2+(-8)^2=36+64=100
x+y=-14
If x and y are not integers,there are many values possible for x and y.
(sqrt(50))^2+((sqrt(50))^2=100
(sqrt(25))^2+((sqrt(75))^2=100
Hope this clarify..
