psm12se wrote:If a rectangle is inscribed in a circle of radius 5, is the area of the rectangle greater than 48
A. The ratio of the lengths of sides of the rectangle is 3:4
B. The difference between the lengths of sides of the rectangle is smaller than 3
Hi
Psm12se,
Here are few thing to note,
1) any Side of a rectangle can't be more than 10. since diameter is 10.
2) Side need not only be integers.
3) Diagonal of an inscribed rectangle is always the diameter of a circle.
To Find: IS Area > 48 (Yes/No Type)
Statement 1: l/b =The ratio of the lengths of sides of the rectangle is 3:4
so sides should be 6 and 8 (6^2+8^2 =100)
6*8 =48 !>48
Hence Sufficient.
Statement 2: The difference between the lengths of sides of the rectangle is smaller than 3
sides can be 6 and 8 (6^2+8^2 =100) 8-6 =2 <3 6*8 =48 =NO
Side can be 5sqrt(2) 5sqrt(2) (50+50=100): 0<3 50 >48 Yes
Hence In-sufficient.
Hence Answer is
A
Regards,
Uva.