pims wrote:Is xy > 0?
(1) x - y > -2
(2) x - 2y < -6
Target question: Is xy > 0?
Statement 1: x - y > -2
There are several values of x and y that satisfy this condition. Here are two:
Case a: x = 1 and y = 1, in which case xy = (1)(1) = 1. Here,
xy > 0
Case b: x = 1 and y = -1, in which case xy = (1)(-1) = -1. Here,
xy < 0
Since we cannot answer the
target question with certainty, statement 1 is NOT SUFFICIENT
Statement 2: x - 2y < -6
There are several values of x and y that satisfy this condition. Here are two:
Case a: x = 1 and y = 10, in which case xy = (1)(10) = 10. Here,
xy > 0
Case b: x = -10 and y = 1, in which case xy = (-10)(1) = -10. Here,
xy < 0
Since we cannot answer the
target question with certainty, statement 2 is NOT SUFFICIENT
Statements 1 and 2 combined
Statement 1: x - y > -2
Statement 2: x - 2y < -6
IMPORTANT: We can solve this system of inequalities (through addition) as long as we get the INEQUALITIES FACING THE SAME DIRECTION first.
Keep statement 1 as is: x - y > -2
Multiply statement 2 by -1 to get: -x + 2y > 6
ADD the inequalities to get:
y > 4
In other words, y IS POSITIVE
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Let's do this one more time.
Statement 1: x - y > -2
Statement 2: x - 2y < -6
Multiply statement 1 by 2 to get: 2x - 2y > -4
Multiply statement 2 by -1 to get: -x + 2y > 6
ADD the inequalities to get:
x > 2
In other words, x IS POSITIVE
If x and y are BOTH POSITIVE,
we can be certain that xy > 0
Since we can answer the
target question with certainty, the combined statements are SUFFICIENT
Answer =
C
Cheers,
Brent