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shekhar.kataria
- Master | Next Rank: 500 Posts
- Posts: 268
- Joined: Mon Mar 15, 2010 12:10 am
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Find the solution to the inequality :
2x+5
------------ <3
|x| +1
1.x < -2/5 or x > 1
2.x < -1 or x > 2/5
3.x < -2/5 or x > 2
4.x > -2/5 or x < 2
5.x > 1 or x < -1
Pleas tell what is the problem within my approach :-
I am considering two secanarios, one is X>=0 and other is X<0; X can not be zero because if X=0 , inequality doesn't stand correct.
FOR X>0 ;
2x+5
------------ <3
x +1
Solving this will give X>2
For X<0 i.e value of X as negative
-2x+5
------------ <3
x +1
Doubt 1:- IS the above expression true when X<0;
Dount 2:- If yes, then after solving this i am getting X>2/5, which is not a solution of this.
Where i am wrong in getting concept of inequality. Please explain
2x+5
------------ <3
|x| +1
1.x < -2/5 or x > 1
2.x < -1 or x > 2/5
3.x < -2/5 or x > 2
4.x > -2/5 or x < 2
5.x > 1 or x < -1
Pleas tell what is the problem within my approach :-
I am considering two secanarios, one is X>=0 and other is X<0; X can not be zero because if X=0 , inequality doesn't stand correct.
FOR X>0 ;
2x+5
------------ <3
x +1
Solving this will give X>2
For X<0 i.e value of X as negative
-2x+5
------------ <3
x +1
Doubt 1:- IS the above expression true when X<0;
Dount 2:- If yes, then after solving this i am getting X>2/5, which is not a solution of this.
Where i am wrong in getting concept of inequality. Please explain
Restlessness and discontent are the first necessities of progress.--Thomas A. Edison
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