prithviforever wrote:if -2x > 3y ,is x negative?
1. y>0
2. 2x+5y-20=0
1) y>0;
multiplying 3 on both sides we have;
3y>0;
for -2x to become greater than 3y; x must be negative; because positive quantity is always greater than negative quantity, hence x must be negative, hence 1 alone is sufficient to answer the question.
2) 2x+5y=20;
also -2x>3y can be written as; 3y+2x<0;
2x+3y=20-2y;
now since 3y+2x<0; i.e. left hand side is negative therefore rhs must also be negative;
i.e. 20-2y<0;
20<2y;
10<y;since y>10; i.e. y is positive and greater than 10, therefore inequality will hold true only if x is negative,, hence 2 alone is also sufficient to answer this question..!!!
hence answer should be
DO Excellence... my search for you is on... you can be far.. but not beyond my reach!
