well it has to be D

st 1 can be thought as follows :in triangle EBC BC = EC =12 that means angles CEB = angle CBE thant concludes us to the fact that angle ABE is also 30 degree !!
so now u know the base as 12 and u know the ht and hence we can find the area of triangle EBC

st 2 is rather simple : all u r given is the area of a triangle b/w two two parallel lines with base as 6 and then u are asked the area of a triangle b/w those same parallel lines with base as 12 .honestly i didn't calculate st 2 .logically we know we can get the area !!

can anyone elaborate on statement 1...how did you prove AB to be the height

@Neha ...how did u prove st 1 : "can be thought as follows :in triangle EBC BC = EC =12 that means angles CEB = angle CBE thant concludes us to the fact that angle ABE is also 30 degree !"

@Neha ...how did u prove st 1 : "can be thought as follows :in triangle EBC BC = EC =12 that means angles CEB = angle CBE thant concludes us to the fact that angle ABE is also 30 degree !"

AB bisects the side CE doesn't mean AB bisects the angle CBE.
This is a common misconception.

Refer to the diagram below.

i guess i did major part of calculation on my paper and didnt write it here !!
when i know that BC = EC =12 then in triangle ABC we have the following : (6/sin30) = (12/ sin BAC)
this gives us sin BAC = 1 ------> angle BAC =90 degree ----> angle ABE = 30

thank u neha