geometry - SemiCircle

This topic has expert replies
Master | Next Rank: 500 Posts
Posts: 275
Joined: Wed Jul 02, 2008 4:19 am
Thanked: 4 times

geometry - SemiCircle

by Xbond » Mon Aug 03, 2009 10:48 pm
Hi there,

I woud like your input about this difficult geometry question. Someone can explain to me in simple way the concept. Sorry, I don't know the answer. Look at the attachment.


In the figure shown, point O is the center of the semicircle and points B, C, and D lie on the semicircle. If the length of the line segment AB is equal to the length of linesegment OC, what is the degree measure of angle BAO ?

(1) The degree measure of angle COD is 60°.
(2) The degree measure of angle BCD is 40°.
Attachments
Q3.doc
(24 KiB) Downloaded 123 times
Source: — Data Sufficiency |

Junior | Next Rank: 30 Posts
Posts: 18
Joined: Fri Jul 24, 2009 2:58 am
Thanked: 2 times

by Matmasi » Wed Aug 26, 2009 2:14 am
statement 1) cod = 60

What we see is that triangle OAB and triangle OBC are both isosceles, so they have two sides and two angles equal. We know that they are isosceles because they both have two sides that are equal to the radius of the semicircle.

So we know that angles OAB and AOB are equal. Let's call them x. So, angle OBA = 180-2x
For the properties of the sum f the exterior angle we know that OBC is equal to 180- (180-2x) = 2x.
Now, we know that also OBC and OCB are equal, so they are both 2x.

From statement 1 we know that angle COA is 120 and so 180=120+x+2x so x = 20
in other words 180= the sum of the angles of the triangle OCA

From statement 2:
BCO = 40
BCO =2x
x = 20

So the answer is D.




Now
BAO + COA + ACO = 180 and we know COA = 120
thus BAO + ACO = 60

Moreover we know that BO=CO cause they are radius, so the triangle OBC is isosceles.
So we also deduct that angle OCA and OBC must be equal
so OCA = OBC

so, bao + cbo =60
cbo = 2bao
hence bao = 20 and suff.

statement 2) aco = 40
aco = cbo
cbo = 2bao
hence bao = 20 and suff.

User avatar
Master | Next Rank: 500 Posts
Posts: 116
Joined: Wed Mar 14, 2012 1:02 pm
Thanked: 20 times
Followed by:11 members
GMAT Score:760

by mcdesty » Tue Jul 08, 2014 5:50 pm
See Img
Attachments
Circle.jpg

User avatar
GMAT Instructor
Posts: 15539
Joined: Tue May 25, 2010 12:04 pm
Location: New York, NY
Thanked: 13060 times
Followed by:1906 members
GMAT Score:790

by GMATGuruNY » Wed Jul 09, 2014 3:02 am
Image

In the figure shown, point O is the center of the semicircle and points B, C, and D lie on the semicircle. If the length of line segment AB is equal to the length of line sement OC, what is the degree measure of angle BAO?

(1) The degree measure of angle COD is 60.
(2) The degree measure of angle BCO is 40.
It is given that AB=OC.
Since OC and OB are both radii, OC=OB.
Thus:
Image

EVALUATE THE EASIER STATEMENT FIRST.
Since statement 2 gives information about one of the equal angles, start with statement 2.

Statement 2: The degree measure of angle BCO is 40.
The result is the following combination of angles:
Image
Thus, angle BAO = 20.
SUFFICIENT.

Statement 1: The degree measure of angle COD is 60.
In the combination of angles yielded by statement 2, angle COD = 60.
Thus, statement 1 implies the same combination of angles as does statement 2.
SUFFICIENT.

The correct answer is D.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3