BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem
TTP OnDemand GMAT Video Course
Featured Course

Target Test Prep GMAT OnDemand

Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.

  • 715+ score guarantee — highest in the industry (99th percentile)
  • 52 chapters · 1,500+ lessons · 4,000+ practice questions
  • 400 hours of video · 1,500+ instructor-led HD smartboard lessons
  • 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
  • 24/7 live support + weekly Zoom office hours with GMAT instructors
  • TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
  • 1,200+ flashcards + AI-powered study assistant & daily calendar
  • OnDemand, LiveTeach & GMAT Bootcamp formats available
  • Also: GRE, SAT Math & Executive Assessment courses
  • MBA Admissions Consulting now available
  • 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
  • 200,000+ students served
  • 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★ 5.0 (559 reviews)
130-pt guarantee
$0 to start then $127/mo
Start Free 5-Day Trial Read 559 Reviews →

permutation

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Junior | Next Rank: 30 Posts
Posts: 10
Joined: Fri Apr 20, 2007 1:18 pm
by recocollins » Tue Jul 31, 2007 3:44 pm
Nine students are split into three equal teams to develop reports on one of three problem: shortage of skilled labor, violence in schools, and low standardized test. How many different teams of students are possible?

A. 5040
B. 1680
C. 1512
D. 504
E. 168

Eight Alaskan Huskies are split into pairs to pull one of four sleds in a race. How many different assignments of Huskies to sleds are possible?

A. 32
B. 64
C. 420
D. 1680
E. 2520

Thanks for your support.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |
Junior | Next Rank: 30 Posts
Posts: 26
Joined: Thu Jul 05, 2007 12:53 pm
Location: Nashville

by lanter1 » Tue Jul 31, 2007 4:05 pm
1.9c3*3!=504

2.8c4*4c2=402

If these are correct, i will explain my reasoningn later. I'm in a hurry at work.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Legendary Member
Posts: 519
Joined: Sat Jan 27, 2007 7:56 am
Location: India
Thanked: 31 times

by Neo2000 » Tue Jul 31, 2007 5:19 pm
(9C3 x 6C3 x 3C3)/3! is the number of ways of splitting 3 students into three different groups
Since they are going to tackle 3 different problems
((9C3 x 6C3 x 3C3)/3! ) x3! = 1680
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Junior | Next Rank: 30 Posts
Posts: 26
Joined: Thu Jul 05, 2007 12:53 pm
Location: Nashville

by lanter1 » Wed Aug 01, 2007 5:46 am
Do we have an OA on these?
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Senior | Next Rank: 100 Posts
Posts: 65
Joined: Tue Jun 12, 2007 12:57 am

by erdnah » Wed Aug 01, 2007 6:26 am
1. 9!/3!3!3! = 1,680
2. 8!/2!2!2!2! = 2,520

May be I'm wrong?!
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Legendary Member
Posts: 986
Joined: Wed Dec 20, 2006 11:07 amFollowed by: 1 member
Location: India
Thanked: 51 times

by gabriel » Wed Aug 01, 2007 7:25 am
erdnah wrote:1. 9!/3!3!3! = 1,680
2. 8!/2!2!2!2! = 2,520

May be I'm wrong?!
nope .. ur right ..
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Junior | Next Rank: 30 Posts
Posts: 26
Joined: Thu Jul 05, 2007 12:53 pm
Location: Nashville

by lanter1 » Wed Aug 01, 2007 8:06 am
erdnah or gabriel, can you explain?
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Legendary Member
Posts: 986
Joined: Wed Dec 20, 2006 11:07 amFollowed by: 1 member
Location: India
Thanked: 51 times

by gabriel » Wed Aug 01, 2007 10:52 am
Ok .. this is the question ..

Eight Alaskan Huskies are split into pairs to pull one of four sleds in a race. How many different assignments of Huskies to sleds are possible?

A. 32
B. 64
C. 420
D. 1680
E. 2520

we have to divide the 8 alaskan huskies into 4 groups of 2 each ..

the first 2 can be selected in 8c2 ways ..

the second group can be selected in 6c2 ways ( 6 bcoz that is the number of huskies left after the first group is chosen) ..

similarly the 3rd group can be chosen in 4c2 ways..

the last group can be chosen in 2c2 ways ..

so the total no. of ways in which the 8 alaskan huskies can be divided into 4 groups of 2 each is = 8c2*6c2*4c2*2c2 .. which is basically equal to 8!/( 2!*2!*2!*2!) ..

PS : if the problem asked us to only divide the 8 huskies into 4 groups then we would have to divide the answer by 4! .. so the evntual answer wuld be 8!/( 2!*2!*2!*2!*4!) ..

but over here the question asks us to divide the 8 huskies into 4 groups each of which will be assigned to a different sled .. so we wont divide the answer by 4! ..
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1