-
shanice
- Master | Next Rank: 500 Posts
- Posts: 110
- Joined: Thu Apr 05, 2012 8:48 am
- Thanked: 3 times
- Followed by:1 members
Hi all,
1)List S consists of 10 consecutive odd integers, and List T consists of 5 consecutive even
integers. If the least integer in S is 7 more than the least integer in T, how much greater is the
average(arithmetic mean) of the integers in S than the average of the integers in T?
A)2 B)7 C)8 D)12 E)22
Answer is D.
My workings:-
S={1,3,5,7,9,11,13,15,17,19}
Mean = 100/10 = 10
T={2,4,6,8,10}
Mean = 30/5 = 6
Am I correct so far with the above? I don't understand how do I apply this sentence"If the least integer in S is 7 more than the least integer in T"?
2)If b<2 and 2x-3b=0, which of the following must be true?
A)x > 3
b)x < 2
c)x=3
d)x < 3
e)x > 3
Answer is D.
I did plug in numbers but it's not working. I may be wrong.
Please help me with the above two questions.
Thank you.
1)List S consists of 10 consecutive odd integers, and List T consists of 5 consecutive even
integers. If the least integer in S is 7 more than the least integer in T, how much greater is the
average(arithmetic mean) of the integers in S than the average of the integers in T?
A)2 B)7 C)8 D)12 E)22
Answer is D.
My workings:-
S={1,3,5,7,9,11,13,15,17,19}
Mean = 100/10 = 10
T={2,4,6,8,10}
Mean = 30/5 = 6
Am I correct so far with the above? I don't understand how do I apply this sentence"If the least integer in S is 7 more than the least integer in T"?
2)If b<2 and 2x-3b=0, which of the following must be true?
A)x > 3
b)x < 2
c)x=3
d)x < 3
e)x > 3
Answer is D.
I did plug in numbers but it's not working. I may be wrong.
Please help me with the above two questions.
Thank you.
