BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Rectangle DS

This topic has expert replies
Post new topic Post Reply
Previous Topic Next Topic
Master | Next Rank: 500 Posts
Posts: 113
Joined: Sun May 24, 2009 8:01 am
Thanked: 4 times

Rectangle DS

by italian7745 » Sat Jun 12, 2010 11:14 pm
If the diagonals of rectangle ABCD ( AB>BC ) cross at point E, what is the value of Angle AEB ?

1) The value of angle EDC is 15 degrees
2) The value of angle ACB is 75 degrees
Top
Source: — Data Sufficiency |

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 1179
Joined: Sun Apr 11, 2010 9:07 pm
Location: Milpitas, CA
Thanked: 447 times
Followed by:88 members

by Rahul@gurome » Sun Jun 13, 2010 1:08 am
(1) The diagonals in a rectangle bisect each other, so DE = CE. So, triangle DEC is an isosceles triangle.
Hence, Angle DEC = 180º - (15º + 15º) = 150º, and angle DEC = angle AEB (vertically opposite angles). So, Angle AEB = 150º.
So, (1) is SUFFICIENT to answer the question.

(2) Angle BCD = 90º implies angle ECD = 90º - 75º = 15º = angle EDC.
Hence, Angle DEC = 180º - (15º + 15º) = 150º, and angle DEC = angle AEB (vertically opposite angles). So, Angle AEB = 150º.
So, (2) is SUFFICIENT to answer the question.

The correct answer is (D).
Image
Rahul Lakhani
Quant Expert
Gurome, Inc.
https://www.GuroMe.com
On MBA sabbatical (at ISB) for 2011-12 - will stay active as time permits
1-800-566-4043 (USA)
+91-99201 32411 (India)
Top
Post new topic Post Reply
• Page 1 of 1