(1) The diagonals in a rectangle bisect each other, so DE = CE. So, triangle DEC is an isosceles triangle.
Hence, Angle DEC = 180º - (15º + 15º) = 150º, and angle DEC = angle AEB (vertically opposite angles). So, Angle AEB = 150º.
So, (1) is SUFFICIENT to answer the question.
(2) Angle BCD = 90º implies angle ECD = 90º - 75º = 15º = angle EDC.
Hence, Angle DEC = 180º - (15º + 15º) = 150º, and angle DEC = angle AEB (vertically opposite angles). So, Angle AEB = 150º.
So, (2) is SUFFICIENT to answer the question.
The correct answer is (D).
Rahul Lakhani
Quant Expert
Gurome, Inc.
https://www.GuroMe.com
On MBA sabbatical (at ISB) for 2011-12 - will stay active as time permits
1-800-566-4043 (USA)
+91-99201 32411 (India)
