BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem
TTP OnDemand GMAT Video Course
Featured Course

Target Test Prep GMAT OnDemand

Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.

  • 715+ score guarantee — highest in the industry (99th percentile)
  • 52 chapters · 1,500+ lessons · 4,000+ practice questions
  • 400 hours of video · 1,500+ instructor-led HD smartboard lessons
  • 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
  • 24/7 live support + weekly Zoom office hours with GMAT instructors
  • TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
  • 1,200+ flashcards + AI-powered study assistant & daily calendar
  • OnDemand, LiveTeach & GMAT Bootcamp formats available
  • Also: GRE, SAT Math & Executive Assessment courses
  • MBA Admissions Consulting now available
  • 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
  • 200,000+ students served
  • 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★ 5.0 (559 reviews)
130-pt guarantee
$0 to start then $127/mo
Start Free 5-Day Trial Read 559 Reviews →

If \(X\) is the hundredths digit in the decimal \(0.1X\) and if \(Y\) is the thousandths digit in the decimal \(0.02Y,\)

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Legendary Member
Posts: 1622
Joined: Thu Mar 01, 2018 7:22 amFollowed by: 2 members
by Gmat_mission » Fri Jan 08, 2021 4:39 am

Timer

00:00

Answers

A

B

C

D

E

Stats

Difficulty—

If \(X\) is the hundredths digit in the decimal \(0.1X\) and if \(Y\) is the thousandths digit in the decimal \(0.02Y,\) where \(X\) and \(Y\) are nonzero digits, which of the following is closest to the greatest possible value of \(\dfrac{0.1X}{0.02Y}?\)

A. 4
B. 5
C. 6
D. 9
E. 10

Answer: D

Source: Official Guide
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 16207
Joined: Mon Dec 08, 2008 6:26 pmFollowed by: 1268 members
Location: Vancouver, BC
Thanked: 5254 times
GMAT Score:770

Re: If \(X\) is the hundredths digit in the decimal \(0.1X\) and if \(Y\) is the thousandths digit in the decimal \(0.02

by Brent@GMATPrepNow » Sat Jan 09, 2021 5:57 am
Gmat_mission wrote: ↑
Fri Jan 08, 2021 4:39 am
 If \(X\) is the hundredths digit in the decimal \(0.1X\) and if \(Y\) is the thousandths digit in the decimal \(0.02Y,\) where \(X\) and \(Y\) are nonzero digits, which of the following is closest to the greatest possible value of \(\dfrac{0.1X}{0.02Y}?\)

A. 4
B. 5
C. 6
D. 9
E. 10

Answer: D

Source: Official Guide
To MAXIMIZE the value of 0.1X/0.02Y, we must MAXIMIZE the numerator (0.1X) and MINIMIZE the denominator (0.02Y)

So, the numerator is maximized when X = 9. So, the numerator is 0.19
The denominator is minimized when Y = 1. So, the denominator is 0.021

So, we must determine the value of 0.19/0.021

IMPORTANT: We need not calculate the value of 0.19/0.021
Instead, just recognize that 0.19/0.02 = 9.5, which is halfway between 9 and 10
Since 0.021 is a bit bigger than 0.02, we know that 0.19/0.021 is a bit LESS THAN 9.5
So, 0.19/0.021 must be closest to 9

Answer: D
Brent Hanneson - Creator of GMATPrepNow.com
Image
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 8144
Joined: Sat Apr 25, 2015 10:56 amFollowed by: 29 members
Location: Los Angeles, CA
Thanked: 43 times

Re: If \(X\) is the hundredths digit in the decimal \(0.1X\) and if \(Y\) is the thousandths digit in the decimal \(0.02

by Scott@TargetTestPrep » Tue Jan 19, 2021 8:18 am
Gmat_mission wrote: ↑
Fri Jan 08, 2021 4:39 am
 If \(X\) is the hundredths digit in the decimal \(0.1X\) and if \(Y\) is the thousandths digit in the decimal \(0.02Y,\) where \(X\) and \(Y\) are nonzero digits, which of the following is closest to the greatest possible value of \(\dfrac{0.1X}{0.02Y}?\)

A. 4
B. 5
C. 6
D. 9
E. 10

Answer: D

Source: Official Guide
Solution:

We are given two decimals:

0.1X and 0.02Y

To make 0.1X the greatest, we can let X = 9 and we have:

0.19

To make 0.02Y the smallest, we can make Y = 1 (since Y = 0 is not allowed) and we have:

0.021

Thus:

0.19/0.021 = 190/21 = 9 1/21

So, the greatest possible value is about 9.

Answer: D

Scott Woodbury-Stewart
Founder and CEO
[email protected]

Image

See why Target Test Prep is rated 5 out of 5 stars on BEAT the GMAT. Read our reviews

ImageImage
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1