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Chris mixed 3 pounds of raisins with 4 pounds of nuts

Expert replies
by BTGmoderatorLU » Wed Apr 25, 2018 3:34 pm

Timer

00:00

Answers

A

B

C

D

E

Stats

Difficulty

Chris mixed 3 pounds of raisins with 4 pounds of nuts. If a pound of nuts costs 3 times as much as a pound of raisins, then the total cost of the raisins was what fraction of the total cost of the mixture?

A. 1/7
B. 1/5
C. 1/4
D. 1/3
E. 3/7

The OA is B.

1 lbs of raisin = $1
3 lbs of raisin = $3

1 lbs of nuts = $3
4 lbs of nuts = $12

Total value of mixture = 12+3 = 15

Fraction of the value of raisin = 3/15 = 1/5

Please, can anyone explain another way to solve this PS question? Thanks!
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Source: — Problem Solving |

by Jay@ManhattanReview » Wed Apr 25, 2018 8:09 pm
BTGmoderatorLU wrote:Chris mixed 3 pounds of raisins with 4 pounds of nuts. If a pound of nuts costs 3 times as much as a pound of raisins, then the total cost of the raisins was what fraction of the total cost of the mixture?

A. 1/7
B. 1/5
C. 1/4
D. 1/3
E. 3/7

The OA is B.

1 lbs of raisin = $1
3 lbs of raisin = $3

1 lbs of nuts = $3
4 lbs of nuts = $12

Total value of mixture = 12+3 = 15

Fraction of the value of raisin = 3/15 = 1/5

Please, can anyone explain another way to solve this PS question? Thanks!
This is all fine.

-Jay
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by Scott@TargetTestPrep » Fri Apr 27, 2018 9:32 am
BTGmoderatorLU wrote:Chris mixed 3 pounds of raisins with 4 pounds of nuts. If a pound of nuts costs 3 times as much as a pound of raisins, then the total cost of the raisins was what fraction of the total cost of the mixture?

A. 1/7
B. 1/5
C. 1/4
D. 1/3
E. 3/7
We can let the cost of a pound of raisins = r and the cost of a pound of nuts = 3r.

The total cost of the mixture is 3r + 4(3r) = 15r.

So raisins were 3r/15r = 1/5 of the total cost of the mixture.

Answer: B

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