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positive integer

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by Xbond » Fri Aug 14, 2009 12:30 am
Hi there,

I would like to know the simplest process to resolve this DS. Explanation is requested.

Is positive integer n divisible by 3 ?
(1) n(square)/36 is an integer.
(2) 144/n2 is an integer
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Source: — Data Sufficiency |
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by tohellandback » Fri Aug 14, 2009 2:17 am
IMO A

1)n^2=36k
n^2=2^2*3^2*k
whatever be the value of k. n must have atlest one 3 as a factor.
SUFF

2) n^2*k=144=3^2*2^4
here it will depend upon k, n may or may not have 3 as a factor
for ex:n=16,k=9
and n=3,k=16
The powers of two are bloody impolite!!
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by Xbond » Mon Aug 17, 2009 5:19 am
many thks guys

OA is A
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