29.If g is the greatest common divisor of k+7 and n, where n and k are integers. g=?
1) n=20891
2) n=k+6
oa B
1) n=20891
2) n=k+6
oa B
1 is not sufficient. We do not have any clues concerning k: it could be whatever, even a multiple of n = 20891....
2 is sufficient. k+6 and k+7 have only one common divisor: 1. Say x divides k+6. Dividing k+7 by x will give you a remainder of 1, no matter what the value of x is.
Answer: B
