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by MBA.Aspirant » Sun Jul 10, 2011 1:55 am
The probability of picking the outcome of two different horse races is 1/63. If the probability of picking neither horse is 40/63, then what is the probability that you will pick at least one horse correctly?

(A) 2/9 (B) 1/3 (C) 8/21 (D) 22/63 (E) 23/63
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by pemdas » Sun Jul 10, 2011 2:53 am
if we rely on dependent events then, 1-40/63=23/63 and 23/63-1/63=22/63 makes it d
MBA.Aspirant wrote:The probability of picking the outcome of two different horse races is 1/63. If the probability of picking neither horse is 40/63, then what is the probability that you will pick at least one horse correctly?

(A) 2/9 (B) 1/3 (C) 8/21 (D) 22/63 (E) 23/63
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