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tough geometry problem
Source: Beat The GMAT — Problem Solving |
I'm guessing C too. Definitely not A or B because the opposing angle can move. I'm not the best guy to explain geometry problems because I just "see" the solution in my head and I play with the shape (in my head).
If both of the lines are locked (because the 2 triangles are isoceles), then sliding the lines up and down does not alter the angle of x. Havign said that, I'm not precisely sure what x would be but I'm fairly sure that it's a constant solution and therefore C is the answer.
If both of the lines are locked (because the 2 triangles are isoceles), then sliding the lines up and down does not alter the angle of x. Havign said that, I'm not precisely sure what x would be but I'm fairly sure that it's a constant solution and therefore C is the answer.
Ans is C
A and B alone are insufficient bcoz one side of angle is not fixed.
and the angle will be equal to 45 degree
A and B alone are insufficient bcoz one side of angle is not fixed.
and the angle will be equal to 45 degree
Is the angle 45 ?
I am getting the angle as 67.5 though I am getting answer as "C" as well
My mistake, I see what I missed.
I am getting the angle as 67.5 though I am getting answer as "C" as well
My mistake, I see what I missed.
How did you actually calculate that X=45? Can you step through the things you inferred?rohangupta83 wrote:imo C
X = 45 degrees
what's OA?
Sure jsl
here it is:
angle P = 90 degress
and
LP + LR + LT = 180...................................1
LRQS + LRSQ + LR = 180..........................2
LRQS = LRSQ (triangle RQS is an isosceles triangle).............3
equating 1 and 2
LP + LR + LT = LRQS + LRSQ + LR
or
90 + LT = LRQS + LRSQ
plugging equation 3 in the above equation
90 + LT = 2LRSQ
LT = 2LRSQ - 90.................eq 4
Now moving on to triangle TSU
LT + LTSU + LTUS = 180............5
LTSU = LTUS (triangle TSU is an isosceles triangle)
LT + 2 LTSU = 180
substituting for LT from equation 4 in equation 5
2LRSQ - 90 + 2LTSU = 180
2LRSQ + 2LTSU = 270
LRSQ + LTSU = 135.............................equation 6
now,
LRSQ + X + LTSU = 180 (angles on a straight line)
plugging equation 6 in the above equation
X + 135 = 180
or X = 45
here it is:
angle P = 90 degress
and
LP + LR + LT = 180...................................1
LRQS + LRSQ + LR = 180..........................2
LRQS = LRSQ (triangle RQS is an isosceles triangle).............3
equating 1 and 2
LP + LR + LT = LRQS + LRSQ + LR
or
90 + LT = LRQS + LRSQ
plugging equation 3 in the above equation
90 + LT = 2LRSQ
LT = 2LRSQ - 90.................eq 4
Now moving on to triangle TSU
LT + LTSU + LTUS = 180............5
LTSU = LTUS (triangle TSU is an isosceles triangle)
LT + 2 LTSU = 180
substituting for LT from equation 4 in equation 5
2LRSQ - 90 + 2LTSU = 180
2LRSQ + 2LTSU = 270
LRSQ + LTSU = 135.............................equation 6
now,
LRSQ + X + LTSU = 180 (angles on a straight line)
plugging equation 6 in the above equation
X + 135 = 180
or X = 45












