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weakens the conclusion above EXCEPT

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weakens the conclusion above EXCEPT

by PGMAT » Sat Oct 13, 2012 12:51 pm
A greater number of cars are sold in Town P than in Town Q. Therefore, the citizens of Town P spend more time driving their cars, per capita, than do the citizens of Town Q.

Each of the following, if true, weakens the conclusion above EXCEPT:
A.Town P has a larger population than Town Q.
B.Most citizens of Town Q work in Town P and buy their cars there.
C.Many residents of Town P purchase second cars that they use only rarely.
D.Most drivers from Town P tend to drive only during the day, and only within the city limits of Town P.
E.The average price of cars sold in Town P is lower than the average price of cars sold in Town Q.

Please explain your answer.
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by akashkumar1987 » Sat Oct 13, 2012 11:20 pm
I think the answer will be E .
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by gmat6087 » Sun Oct 14, 2012 12:23 am
PGMAT wrote:A greater number of cars are sold in Town P than in Town Q. Therefore, the citizens of Town P spend more time driving their cars, per capital, than do the citizens of Town Q.

Each of the following, if true, weakens the conclusion above EXCEPT:
A.Town P has a larger population than Town Q.
B.Most citizens of Town Q work in Town P and buy their cars there.
C.Many residents of Town P purchase second cars that they use only rarely.
D.Most drivers from Town P tend to drive only during the day, and only within the city limits of Town P.
E.The average price of cars sold in Town P is lower than the average price of cars sold in Town Q.

Please explain your answer.
IMO E but still skeptical about D what is the OA.
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by PGMAT » Sun Oct 14, 2012 6:19 am
Can either of you explain your answer choice? OA is E
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by Sapana » Fri Jan 04, 2013 7:39 pm
I thought the answer was D. People of P driving only during the day and within the limit of P-->How does this weaken the argument?
In fact, in E , the choice says that cars are cheaper in P than in Q which makes a good reason for greater sale in P than in Q. I am confused by the answer given above. Can anyone please help me solve it. What is the source of this question.
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by nash.8087 » Sat Jan 05, 2013 10:50 am
Even i thought it is D. Can someone explain how E qualifies?

Experts, please help.
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by The Iceman » Sat Jan 05, 2013 2:15 pm
The conclusion that we need to evaluate is "the citizens of Town P spend more time driving their cars, per capital, than do the citizens of Town Q"

In trying to weaken, we need not always strive to completely destroy the conclusion. Even mild weakening is enough to qualify the option as a weakener.

If as per D, most drivers from Town P tend to drive only during the day, and only within the city limits of Town P, then they may be spending lesser time because they do not utilize evening or night as much, or do not go on the long drives outside city, which may again give them lesser time to spend driving their cars. On the other hand Town Q may not have such a constrained trend among its citizens.

So, you see, option D works as a weakener.

Option E only talks about the relative average selling price of the cars in the two cities. However, we already know from the argument that more cars are sold in Town P than in Town Q. So there is nothing that E does to address the point about time spent driving cars. So, E is irrelevant and hence the right answer.
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