gdrea3 wrote:I am totally confused as to why the answer isn't D. Seems to me like statements are saying the same thing. I used actual numbers and my answers proved that both statements were sufficient:
Statement 1: pqp=p
So if p=2, then 4p=2 and p=1/2 so p*q does equal one (2*1/2)=1, correct?
Statement 2: qpq=q
So if q=3 then 9p=3, p=1/3 so p*q (3*1/3)=1 sufficient.
?????
When picking numbers in DS, it is important to pick different kinds of numbers that satisfy the statement. You want to see if, through picking numbers, you can prove the statement is NOT sufficient. By picking only one number in statement one, you haven't proved that it is sufficient to answer the question. You've only proved that it could lead to pq = 1; not that it has to.
You are correct that if p = 2, pq = 1. But what if p = 0? Then:
pqp = p
0*q*0 = 0
Clearly, here, pq = 0. So, from statement one, pq can equal 1; but it can also equal 0. Therefore, the first statement is not sufficient. You can apply similar reasoning to statement two, and to the combination of the two statements.
Kaplan Teacher in Toronto