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by vaivish » Wed Jun 25, 2008 8:20 am
In Company X, the number of male employee is twice the number of female employees. The number of male employees who have a master degree is equal to the number of female employees who have a master degree. If 1/5 of the employees in Company X have a master degree, then, what fraction of the male employees do not have a master degree?
(A) 1/5
(B) 2/5
(C) 3/20
(D) 7/10
(E) 17/20
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by AleksandrM » Wed Jun 25, 2008 9:15 am
Set up a matrix:

Work with easy numbers. If there are 50 women, then there are 100 men, = 150 total empoyees.

1/5 of 150 = 30 half of which (15) is men with MS and half female with MS.

Now fill in the rest of your matrix.

Men without an MS = 100 - 15 = 85

Don't need it, but female without an MS = 35.

Anyway, to answer the question:

85/100 reduces to 17/20.

Choose E.
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by atlantic » Wed Jun 25, 2008 9:40 am
Hi Vavish,

M - total number of male employees
F - total number of female employees
Mm - number of male employees with master degree
Fm - number of female employees with master degree

From the statement we know that

(1) M=2F <-> F=1/2M
(2) Mm=Fm
(3) Mm+Fm=1/5(M+F)

Then Mm+Fm=1/5(M+F) <-> 2Mm=1/5(M+1/2M) <-> 2Mm=3/10M

<-> Mm/M=3/20 that can be read as the fraction of male with a master degree.

Obviously, the fraction of male without a master degree is 1-Mm/M = 17/20

Answer E.

Hope it helps.
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by vaivish » Wed Jun 25, 2008 11:03 am
ya its right
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