BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Need Help..Confused concepts

Expert replies
by dddanny2006 » Wed Aug 21, 2013 5:21 am
If d is a positive integer,is sqrt of d an integer?

1.Sqrt of 9d is an integer
2.Sqrt of 10d is NOT an integer.


Now this is how I understand it for Statement 1.

Let the integer be 2,that implies 9d=4 that implies d=4/9 Sqrt of 4/9 is not an integer--------NO

Let the integer be 9,that implies 9d=81,that implies d=9 Sqrt of 9 is 3 which is a integer------YES


Therefore it is insufficient.

Same is the case with Statement 2 as well and hence I think the answer should be E

The book says the answer is A.

Why is my approach incorrect??

Please clarify,


Dan
Join the discussion
Source: — Data Sufficiency |

by Brent@GMATPrepNow » Wed Aug 21, 2013 5:45 am
dddanny2006 wrote: If d is a positive integer, is sqrt(d) an integer?
(1) sqrt(9d) is an integer.
(2) sqrt(10d) is not an integer.
Asde: This is very similar to this question: https://www.beatthegmat.com/og-quant-rev ... tml#688190


Target question: Is sqrt(d) an integer?

Given: d is a positive integer

Statement 1: sqrt(9d) is an integer
IMPORTANT CONCEPT: If K is an integer, then sqrt(K) will be an integer if the prime factorization of K has an even number of each prime.
Some examples:
sqrt(144) = 12 (integer), and 144 = (2)(2)(2)(2)(3)(3) [four 2's and two 3's]
sqrt(1600) = 40 (integer), and 1600 = (2)(2)(2)(2)(2)(2)(5)(5) [six 2's and two 5's]
sqrt(441) = 21 (integer), and 441 = (3)(3)(7)(7)[two 3's and two 7's]
sqrt(12) = some non-integer, and 12 = (2)(2)(3)[two 2's and one 3]

So, if sqrt(9d) is an integer, then the prime factorization of 9d has an even number of each prime.
Since 9d = (3)(3)(d) we can see that the prime factorization of d must have an even number of each prime.
If the prime factorization of d has an even number of each prime, then sqrt(d) must be an integer.
Since we can answer the target question with certainty, statement 1 is SUFFICIENT

Statement 2: sqrt(10d) is NOT an integer.
There are several values of d that meet this condition. Here are two:
Case a: d = 4. This means that sqrt(10d) = sqrt(40), which is not an integer. In this case, sqrt(d) is an integer.
Case b: d = 5. This means that sqrt(10d) = sqrt(50), which is not an integer. In this case, sqrt(d) is not an integer.
Since we cannot answer the target question with certainty, statement 2 is NOT SUFFICIENT

Answer = A

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
Image
Join the discussion

by Brent@GMATPrepNow » Wed Aug 21, 2013 5:47 am
dddanny2006 wrote:If d is a positive integer,is sqrt of d an integer?

1.Sqrt of 9d is an integer
2.Sqrt of 10d is NOT an integer.


Now this is how I understand it for Statement 1.

Let the integer be 2,that implies 9d=4 that implies d=4/9 Sqrt of 4/9 is not an integer--------NO

Let the integer be 9,that implies 9d=81,that implies d=9 Sqrt of 9 is 3 which is a integer------YES


Therefore it is insufficient.

Same is the case with Statement 2 as well and hence I think the answer should be E

The book says the answer is A.

Why is my approach incorrect??

Please clarify,


Dan
Hey Dan,

In your solution, you let d = 4/9 , but the question states that d is a positive integer.

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
Image
Join the discussion

by [email protected] » Wed Aug 21, 2013 12:29 pm
Hi dddanny2006,

In this DS question, we are told that d is a positive integer and we're asked if root(d) is an integer? This is a YES/NO question.

Fact 1: root(9d) is an integer.

Using square root rules, we can simplify this expression by pulling out the 9, which gives us...

3(root(d)) = an integer

Since we're restricted to positive integers, d can ONLY be a perfect square = 1, 4, 9, 16, etc.
If d = 1 then the answer to the question is YES
If d = 4 then the answer to the question is YES
If d = 9 then the answer to the question is YES
etc.
Consistent = SUFFICIENT

To beat DS questions, you MUST pay attention to what you're told.

GMAT assassins aren't born, they're made,
Rich
Contact Rich at [email protected]
Image
Join the discussion