Inequality Pbm

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Inequality Pbm

by seema19 » Wed Nov 16, 2011 9:47 am
If X + Y + Z > 0, is Z > 1?
a) Z > X + Y + 1
b) X + Y + 1 < 0

Answer: B

My reasoning was - since Z > 1 + (X + Y), Z is definitely greater than 1. So, A is suff.
Since in option B, the inequality doesn't have Z, it is not enough to answer. So, B is insuff.
Can someone please tell, where I went going wrong in analyzing the first option?
Source: — Data Sufficiency |

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by shankar.ashwin » Wed Nov 16, 2011 9:59 am
X + Y + Z > 0, is Z > 1?

Statement 1 cannot hold true for -ve values.

Consider x = -1, y = -2

X+Y+1 = -2

Given Z > -2 (Z can be -1,0 (or) +ve) - Insufficient.

Statement 2.

X+Y < -1

Sub X+Y = -2 (or) any number < -1 , from question we can surely say Z > 1 - Sufficient. B IMO

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by user123321 » Wed Nov 16, 2011 12:42 pm
a)Z > X + Y + 1
=> 2z > x+y+z+1
=> 2z-1>x+y+z
but from given x+y+z>0 so 2z-1>0
=> z>0.5 so insufficient because this cannot answer us whether z>1 or not

b) X + Y + 1 < 0
=> x+y+z+1<z
=> x+y+z<z-1
but x+y+z>0 so z-1> 0
=> z>1 so it is sufficient this can answer us whether z>1 or not

IMO B
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by GMATGuruNY » Thu Nov 17, 2011 2:19 am
seema19 wrote:If X + Y + Z > 0, is Z > 1?
a) Z > X + Y + 1
b) X + Y + 1 < 0

Answer: B

My reasoning was - since Z > 1 + (X + Y), Z is definitely greater than 1. So, A is suff.
Since in option B, the inequality doesn't have Z, it is not enough to answer. So, B is insuff.
Can someone please tell, where I went going wrong in analyzing the first option?
The question stem gives an inequality.
Each statement gives an inequality.
One strategy is to ADD THE INEQUALITIES.
To add inequalities, the <> must face the same direction in each.

Statement 1: Z > X + Y + 1
Adding together X+Y+Z>0 and Z>X+Y+1, we get:
(X+Y+Z) + Z > 0 + (X+Y+1)
2Z > 1.
Z > 1/2.
INSUFFICIENT.

Statement 2: X + Y + 1 < 0
Adding together X+Y+Z>0 and 0>X+Y+1, we get:
(X+Y+Z) + 0 > 0 + (X+Y+1)
Z > 1.
SUFFICIENT.

The correct answer is B.
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