what is the last digit of 3^(3^3)?
1
3
6
7
9
to me the answer is D
3^(3^3)= 3^(27) since the last digit in power 3 will be 3,9,7,1 and this cycle repeat every 4 and power of the Q is 27, then the 27th power will be 7
what is ur ideas?
1
3
6
7
9
to me the answer is D
3^(3^3)= 3^(27) since the last digit in power 3 will be 3,9,7,1 and this cycle repeat every 4 and power of the Q is 27, then the 27th power will be 7
what is ur ideas?
