Hi Sukhman,sukhman wrote:1^1+2^2+3^3+...+10^10 is divided by 5. What is the remainder?
(A) 0 (B) 1 (C) 2 (D) 3 (E) 4
You have already posted the same question earlier,
https://www.beatthegmat.com/number-systems-t270591.html
Number Systems
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Uva@90
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You have already posted the same question earlier,
https://www.beatthegmat.com/number-systems-t270591.html
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Uva@90
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mevicks wrote:Is the answer B?sukhman wrote:1^1+2^2+3^3+...+10^10 is divided by 5. What is the remainder?
(A) 0 (B) 1 (C) 2 (D) 3 (E) 4
Hi Vivek,
How you concluded OA is B. It should be C.
Regards,
Uva.
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Uva@90
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Here is how I did,
Anything to the power of 1 end in =================1
2^2 =================4
3^3 =================7(3,9,7,1)
4^4 =================6(series go like this, 4,6, same again)
5^5 =================5
6^6 =================6
7^7 =================3(7,9,3,1)
8^8 =================6(8,4,2,6)
9^9 =================9(9,1)
10^10 =================0
Sum ends in 7
7/5 leave reminder 2
Hence C
Anything to the power of 1 end in =================1
2^2 =================4
3^3 =================7(3,9,7,1)
4^4 =================6(series go like this, 4,6, same again)
5^5 =================5
6^6 =================6
7^7 =================3(7,9,3,1)
8^8 =================6(8,4,2,6)
9^9 =================9(9,1)
10^10 =================0
Sum ends in 7
7/5 leave reminder 2
Hence C
