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rakeshd347
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Source: Beat The GMAT — Problem Solving |
- sanju09
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- Uva@90
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Hi Rakesh,
Let X be the total number of staplers.
Out that 10% is Defective => 90% is Non-Defective.
So, (90/100)*X = Total Number of Non-Defective
Of Non defective 2% is Rejected
So, (90/100)*(2/100)* x is Rejected
90 of the Non -Defective staplers has been rejected.
So,
90 = (90/100)*(2/100) * X
Solve for it X= 5000
OA is E
Regards,
Uva.
Let X be the total number of staplers.
Out that 10% is Defective => 90% is Non-Defective.
So, (90/100)*X = Total Number of Non-Defective
Of Non defective 2% is Rejected
So, (90/100)*(2/100)* x is Rejected
90 of the Non -Defective staplers has been rejected.
So,
90 = (90/100)*(2/100) * X
Solve for it X= 5000
OA is E
Regards,
Uva.
- GMATGuruNY
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An alternate approach is the PLUG IN THE ANSWERS, which represent the total number of staplers.
2% of the middle answer choice -- 4500 -- is equal to 90.
But the problem states that 2% of ONLY THE NONDEFECTIVE STAPLERS = 90.
Thus, the total number of staplers must be GREATER than 4500.
Eliminate A, B and C.
Between D and E, E seems easier to evaluate.
E: 5000
Defective = 10% of 5000 = 500.
Nondefective = 5000-500 = 4500.
Rejected nondefective = 2% of 4500 = 90.
Success!
The correct answer is E.
2% of the middle answer choice -- 4500 -- is equal to 90.
But the problem states that 2% of ONLY THE NONDEFECTIVE STAPLERS = 90.
Thus, the total number of staplers must be GREATER than 4500.
Eliminate A, B and C.
Between D and E, E seems easier to evaluate.
E: 5000
Defective = 10% of 5000 = 500.
Nondefective = 5000-500 = 4500.
Rejected nondefective = 2% of 4500 = 90.
Success!
The correct answer is E.
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Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3












