Find the number of consecutive zeros at the end of the following numbers.
100!+ 200!
a.73 b.24 c.11 d.22
100!*200!
a.49 b.73 c.132 d.33
100!+ 200!
a.73 b.24 c.11 d.22
100!*200!
a.49 b.73 c.132 d.33
100! --> 20 + 4 = 24
200! --> 40 + 8 + 1 = 49
Q1.Since, adding 100! will impact 200!... so, 24
Q2.Since, Multiplying.. we will add 24+49 = 73
