IMO ,the answer is C.bhumika.k.shah wrote:An operation θ is defined by the equation a θ b =a - b / a + b , for all numbers a and b such that
a ≠-b. If a ≠-c and a θ c = 0, then c =
(A) -a
(B) -1/a
(C) 0
(D)1/a
(E) a
How to start solving this sum ???
harsh.champ wrote:IMO ,the answer is C.bhumika.k.shah wrote:An operation θ is defined by the equation a θ b =a - b / a + b , for all numbers a and b such that
a ≠-b. If a ≠-c and a θ c = 0, then c =
(A) -a
(B) -1/a
(C) 0
(D)1/a
(E) a
How to start solving this sum ???
harsh.champ wrote:Ok,I get it.bhumika.k.shah wrote:An operation θ is defined by the equation a θ b =a - b / a + b , for all numbers a and b such that
a ≠-b. If a ≠-c and a θ c = 0, then c =
(A) -a
(B) -1/a
(C) 0
(D)1/a
(E) a
How to start solving this sum ???
now, a ≠-c,so a+c ≠0,so addition sign ruled out.
also a+b ≠0 ,
From the question i can figure out that it is componendo and dividendo,
hence a-c/a+c = 0 => a=c.
Hence,answer would be E.
harsh.champ wrote:harsh.champ wrote:Ok,I get it.bhumika.k.shah wrote:An operation θ is defined by the equation a θ b =a - b / a + b , for all numbers a and b such that
a ≠-b. If a ≠-c and a θ c = 0, then c =
(A) -a
(B) -1/a
(C) 0
(D)1/a
(E) a
How to start solving this sum ???
now, a ≠-c,so a+c ≠0,so addition sign ruled out.
also a+b ≠0 ,
From the question i can figure out that it is componendo and dividendo,
hence a-c/a+c = 0 => a=c.
Hence,answer would be E.
aθc = 0bhumika.k.shah wrote:An operation θ is defined by the equation a θ b =a - b / a + b , for all numbers a and b such that
a ≠-b. If a ≠-c and a θ c = 0, then c =
(A) -a
(B) -1/a
(C) 0
(D)1/a
(E) a
How to start solving this sum ???
ajith wrote:aθc = 0bhumika.k.shah wrote:An operation θ is defined by the equation a θ b =a - b / a + b , for all numbers a and b such that
a ≠-b. If a ≠-c and a θ c = 0, then c =
(A) -a
(B) -1/a
(C) 0
(D)1/a
(E) a
How to start solving this sum ???
(a-c)/(a+c) =0
=>
a-c =0
a=c
E
