shashank.ism wrote:Two boats start from the opposite banks of a river simultaneously. They meet at a distance of 410 m from one of the banks and continue sailing further till they reach the opposite banks. They take rest for 1 hr each and start off the return journey. Now they meet at a distance of 230 m from the other bank. Find the distance between the two banks. Note: (Assume that river water is almost still).

a.)750 m
b.) 840 m
c.) 1100 m
d.) 1200 m
e.)1000 m

Let the distance between the banks be x meters
speed of first boat be a and the second boat be b

now, 410/a = x-410/b

b/a = (x-410)/410

Now first boat will reach the other bank in x/a time and second boat will reach there in x/b time and they both take rest for 1 hour

when they meet the second time distance travelled by first boat = x+230
distance travelled by second boat = 2x -230

x+230/a = 2x-230/b

b/a = 2x-230/x+230

x-410/410 = 2x-230/x+230

Now, I would substitute the answers and my luck 1000 comes out to work perfectly
{well for purists (I have been seeing many of them lately)can solve the quadratic equation and find out}