What is the best way not to get tripped up or slowed down by these problems?
{(1000)^2 - (999)^2} / {(101)^2 - (99)^2} =
a. 10
b. 20
c. 40
d. 80
e. 100
OA = 10
{(1000)^2 - (999)^2} / {(101)^2 - (99)^2} =
a. 10
b. 20
c. 40
d. 80
e. 100
OA = 10
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