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GMAT Prep: Combination sum

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by ashokkadam » Sat Oct 02, 2010 11:13 pm
Since we just need combinations and order does not matter.
so, 12C4 = 12!/4! 8! = 9.10.11.12/1.2.3.4 = 9.5.11 = 45.11 = 495
Skywalker wrote:Why is the answer here option 3 i.e. 495. Please let me know,


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by Rahul@gurome » Sat Oct 02, 2010 11:14 pm
Solution:
Since order does not matter here, it is a combination problem.
Number of ways of selecting 4 sites from given 12 sites is 12C4 = (12!)/(8!*4!) = (12*11*10*9)/24 = 495.
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