BTGModeratorVI wrote: ↑Wed Jan 06, 2021 8:18 am
A 400 milliliter solution is 20% alcohol by volume. If 100 milliliters of water is added, what is the new concentration of alcohol, as a percent of volume?
(A) 5%
(B) 10%
(C) 12%
(D) 12.5%
(E) 16%
Answer:
E
Solution:
If a 400-milliliter solution is 20% alcohol by volume, it has 400 x 0.2 = 80 milliliters of alcohol. Thus the concentration of alcohol, when 100 milliliters of water is added, is:
80 / (400 + 100) = 80/500 = 16/100 = 16%
Alternate Solution:
To a 400 ml solution of 20% alcohol, we add 100 ml of water, which has 0% alcohol, and we obtain 500 ml of a solution with x% alcohol. Creating an equation, we have:
400 (0.20) + 100 (0) = 500x
80 + 0 = 500x
0.16 = x
Converted to a percent, we see that x = 16%.
Answer: E
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