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Which must be true? (prime integers)

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by DeepakR » Tue Feb 10, 2009 6:10 pm
Put some values randomly. First try values for y
try y=1 so x has to be 1 to so that 2x/y=2 which is prime but the condition given is 2x/y > 2. So option II y=1 is ruled out.

Now, try y=2 and x=3 we get 2x/y=3 > 2 hence this works. Lets check the same for another value, y=4 and x=6 we get 2x/y=12/4=3 but x and y are not prime in this case so option III is ruled out.

Finally if x=y we get 2x/y=2 always hence option I is ruled out. Is the
Ans.) A none

- Deepak
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by raunekk » Tue Feb 10, 2009 9:50 pm
i agree..A
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by x2suresh » Tue Feb 10, 2009 10:03 pm
agree with Deepak.
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by ellexay » Wed Feb 11, 2009 6:22 am
Unfortunately, I could not access the OA for this one. I did think it was (A) though. Thanks!!!
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