Suppose x is an integer such that (x ^ 2 −x−1)^ (x+2) =1 . How many possible values of x exist?
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(x ^ 2 −x−1)^ (x+2) =1 is possible only whensud21 wrote:Suppose x is an integer such that (x ^ 2 −x−1)^ (x+2) =1 . How many possible values of x exist?
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Either (x ^ 2 −x−1)=1 i.e. x = 2 or -1
OR (x+2) =0 i.e. x = -2
Or x=0
i.e. Possible values of x = 0, 2, -1 and -2
Answer: option D
