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To find: x > y
Statement 1:
x / 4 = y^2
x = 4 * y^2
x = (2y)^2
For Integers, Yes, x > y
For Non-Int, assume y= 0.1 then x=0.04
INSUFFICIENT
Statement 2:
x > 1
we have no info about y
INSUFFICIENT
Combining...
x > 1
x / 4 = y^2 ==> y = sqrt(x) / 2
IF x is INT, then x > y
If x is Non-Int, then also x > y
SUFFICIENT
Answer [spoiler]{C}[/spoiler]?
