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by Anurag@Gurome » Tue Jan 31, 2012 8:16 pm
sud21 wrote:Image

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Distance of (m , n) from (-4, -2) = √[(m + 4)² + (n + 2)²] = √[m² + n² + 8m + 4n + 20]
Distance of (m , n) from (4, 6) = √[(m - 4)² + (n - 6)²] = √[m² + n² - 8m - 12n + 52]
Then [m² + n² + 8m + 4n + 20] = [m² + n² - 8m - 12n + 52]
16m + 16n = 32
m + n = 2 or m = 2 - n

The correct answer is D.
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by pemdas » Tue Jan 31, 2012 8:29 pm
let m and n be the coordinates of a circle's center, then the equation of the circle will be (x-m)^2 + (y-n)^2 = r^2, since we are given equidistant points we can compare by radius and should obtain

(-4-m)^2 +(-2-n)^2 = (4-m)^2 + (6-n)^2
16+8m+m^2+4+4n+n^2=16-8m+m^2+36-12n+n^2
16m-32+16n=0, 16(m+n)=32, m+n=2 and m=2-n

correct answer d
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