Now, the unit's digits of powers of 2 have a cycle of 4.
- # Unit's digit of 2^(multiple of 4) = 6
# Unit's digit of 2^[(multiple of 4) + 1] = 2
# Unit's digit of 2^[(multiple of 4) + 2] = 4
# Unit's digit of 2^[(multiple of 4) + 3] = 8
Say, k = 10, unit's digit of 2^10 = 2^(8 + 2) = 4
Say, k = 20, unit's digit of 2^20 = 6
Not sufficient
Statement 2: Unit's digit of 2^k will be 6.
Sufficient
The correct answer is B.
