For a line passing through the point (0,0) and (a,b), the slope is given by
m = (b-0)/(a-0) = b/a
1. slope < 0 : m<0 : b/a <0
- b is nagative, or
- a is nagative.
insufficient.
2. a<0 , we dont know the value of B.
combining both : a<0 so b > 0 and hence b>a, sufficient.
Hope this helps !!
coordinate
This topic has expert replies
Source: Beat The GMAT — Data Sufficiency |
- sam2304
- Legendary Member
- Posts: 1239
- Joined: Tue Apr 26, 2011 6:25 am
- Thanked: 233 times
- Followed by:26 members
- GMAT Score:680
Check Image - Self explanatory
Combining 1 & 2. a,b is in 2nd quadrant where a is -ve and b is +ve so a < b.
Combining 1 & 2. a,b is in 2nd quadrant where a is -ve and b is +ve so a < b.
- Attachments
-
Getting defeated is just a temporary notion, giving it up is what makes it permanent.
https://gmatandbeyond.blogspot.in/
https://gmatandbeyond.blogspot.in/
-
ArunangsuSahu
- Master | Next Rank: 500 Posts
- Posts: 382
- Joined: Thu Mar 31, 2011 5:47 pm
- Thanked: 15 times
Think about the Gradient rule of COORDINATE GEOMETRY:
passes through origin so m=a/b= 1 or -1
Statement 1:
Slope <0
from the above either a< 0 or b<0..So INSUFFICIENT
Statement 2:
a< 0
Case I: b<0 => m=a/b=1
Case II: b >0 => m=a/b=-1
INSUFFICIENT
Combining (1) and (2)
a/b < 0(=-1) and a< 0 so b >0
a<b
SUFFICIENT
(C) is the Choice
passes through origin so m=a/b= 1 or -1
Statement 1:
Slope <0
from the above either a< 0 or b<0..So INSUFFICIENT
Statement 2:
a< 0
Case I: b<0 => m=a/b=1
Case II: b >0 => m=a/b=-1
INSUFFICIENT
Combining (1) and (2)
a/b < 0(=-1) and a< 0 so b >0
a<b
SUFFICIENT
(C) is the Choice












