BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

If the ratio of the number of teachers to the number of.....

Expert replies
by factor26 » Wed Dec 07, 2011 5:56 pm
If the ratio of the number of teachers to the number of
students is the same in School District M and School
District P, what is the ratio of the number of students
in School District M to the number of students in
School District P ?

(1) There are 10,000 more students in School
District M than there are in School District P.

(2) The ratio of the number of teachers to the
number of students in School District M is
1 to 20.

OG answer is E ... can someone show me how to solve using the plug in the numbers technique? Much appreciated thanks!
Join the discussion
Source: — Data Sufficiency |

by Anurag@Gurome » Wed Dec 07, 2011 6:35 pm
factor26 wrote:If the ratio of the number of teachers to the number of students is the same in School District M and School District P, what is the ratio of the number of students in School District M to the number of students in School District P ?

(1) There are 10,000 more students in School District M than there are in School District P.

(2) The ratio of the number of teachers to the number of students in School District M is 1 to 20.

OG answer is E ... can someone show me how to solve using the plug in the numbers technique? Much appreciated thanks!
Let the number of teachers and students in school district M are Tm and Sm respectively.
Also let us assume that the number of teachers and students in school district P are Tp and Sp respectively.
It is given that Tm : Sm = Tp : Sp
We have to find Sm : Sp

(1) Sm = 10000 + Sp
So, Sm : Sp = (10000 + Sp) : Sp, but we do not know Sp; NOT sufficient.

(2) Tm : Sm = 1 : 20 = Tp : Sp
Again this is NOT sufficient.

Combining (1) and (2), Sm : Sp = (10000 + Sp) : Sp and Tm : Sm = 1 : 20 = Tp : Sp, but again we do not get the ratio of Sm to Sp using this information; NOT sufficient.

The correct answer is E.
Anurag Mairal, Ph.D., MBA
GMAT Expert, Admissions and Career Guidance
Gurome, Inc.
1-800-566-4043 (USA)

Join Our Facebook Groups
GMAT with Gurome
https://www.facebook.com/groups/272466352793633/
Admissions with Gurome
https://www.facebook.com/groups/461459690536574/
Career Advising with Gurome
https://www.facebook.com/groups/360435787349781/
Join the discussion

by vijaykondepudi » Wed Dec 19, 2012 7:57 am
Hi,
In this question we need to find the ratio: Sm/Sp

I am unable to understand, why statement 2 is not sufficient.

Tm:Sm = 1:20 = Tp:Sp ---> Equation 2

From the above, can we write as follows :

Tm:Tp = 1:20 = Sm:Sp

Can't we then conclude that Sm:Sp = 1:20 (This is the ratio that's require)

I tried a few values:
Assume, Tm = 1, Sm = 20 ; Tp = 20, Sp = 400.

Therefore, the ratio Tm:Sm = 1:20 = Tp:Sp is valid for the above assumption.

Now, from this I can calculate Sm:Sp = 20:400 = 1:20

So why is Statement (2) alone not sufficient? Please explain in detail.
Join the discussion

by GMATGuruNY » Wed Dec 19, 2012 2:41 pm
factor26 wrote:If the ratio of the number of teachers to the number of
students is the same in School District M and School
District P, what is the ratio of the number of students
in School District M to the number of students in
School District P ?

(1) There are 10,000 more students in School
District M than there are in School District P.

(2) The ratio of the number of teachers to the
number of students in School District M is
1 to 20.
Each district has the same teacher-student ratio.
Statement 2 implies that, in each district, the number of teachers is 1/20 of the number of students.
The following cases satisfy BOTH statements.

CASE 1:

_________________P_____________M

Students_______2000________12000

Teachers_______100___________600

Here, the student ratio = 2000:12000 = 1:6.

CASE 2:

__________________P_____________M

Students_______10000________20000

Teachers________500__________1000

Here, the student ratio = 10000:20000 = 1:2.

Since different student ratios are possible, the two statements combined are INSUFFICIENT.

The correct answer is E.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Join the discussion

by vijaykondepudi » Wed Dec 19, 2012 6:46 pm
Hi Mitch,

Thanks for your explanation :)
But in general, doesn't the "Cross Multiplication" rules apply, when we have 3 ratios ?

For, example:

a:b = 1:20
c:d = 1:20

Does it mean that we cannot equate as follows :

a:b = c:d ??

Your examples are pretty clear, but from arithmetic point of view, why is cross multiplication valid for 2 ratios and not when combining 3 ratios ?

Please explain.
Join the discussion