- cypherskull
- Senior | Next Rank: 100 Posts
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Statement 1: x > (y - 2)cypherskull wrote:Is xy > 0?
(1) x - y > -2
(2) x - 2y < -6
x and y can have any sign.
For example,
- x = 2, y = 2 --> x > (y - 2) --> xy > 0
x = 2, y = 0 --> x > (y - 2) --> xy = 0
Statement 2: x < (2y - 6)
x and y can have any sign.
For example,
- x = 2, y = 8 --> x < (2y - 6) --> xy > 0
x = 0, y = 4 --> x < (2y - 6) --> xy = 0
1 & 2 Together: (y - 2) < x < (2y - 6)
Hence, (y - 2) < (2y - 6) ---> y > 4
Therefore, x > (y - 2) = (4 - 2) = 2 > 0
Therefore, xy > 0
Sufficient
The correct answer is C.













