BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

9 a factor of 2x

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Master | Next Rank: 500 Posts
Posts: 222
Joined: Mon Oct 13, 2008 4:04 pmFollowed by: 2 members
Thanked: 3 times
by venmic » Sat Jun 04, 2011 8:08 pm
9 factor of 2x


if 9 is a factor of 2x then which of the following may not be an integer?

A) 6x/54 + 2x/3
B) (4x-18)/9
C) (2x+27)/9
D) (81-4x²)/81
E) (2x-3)/3

[spoiler]Answer A
[/spoiler]
what if X is 54 then A IS an integer

Source Kaplan test
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |
Legendary Member
Posts: 1448
Joined: Tue May 17, 2011 9:55 amFollowed by: 53 members
Location: India
Thanked: 375 times

by Frankenstein » Sat Jun 04, 2011 8:17 pm
venmic wrote:9 factor of 2x


if 9 is a factor of 2x then which of the following may not be an integer?

A) 6x/54 + 2x/3
B) (4x-18)/9
C) (2x+27)/9
D) (81-4x²)/81
E) (2x-3)/3

[spoiler]Answer A
[/spoiler]
what if X is 54 then A IS an integer

Source Kaplan test
Hi,
'may not' is not the same as 'will not'. we are not concerned about when it is an integer. We only need to check if the value can ever not be an integer. So, if we take 2x as odd multiples of 9, op A won't be an integer. But all other options will be integers irrespective of what you take the value of x.
Cheers!

Things are not what they appear to be... nor are they otherwise
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Legendary Member
Posts: 1309
Joined: Mon Apr 04, 2011 5:34 amFollowed by: 123 members
Location: India
Thanked: 310 times
GMAT Score:750

by cans » Sat Jun 04, 2011 8:20 pm
9 is factor of 2x. x=is multiple of 9/2
a)6x/54 + 2x/3 = 7x/9 as x is multiple of 9/2, not sure(7/2 is not integer)
b)(4x-18)/9 2x is multiple of 9 and 18 is also multiple of 9. thus integer
c) (2x+27)/9 = 2x and 27 both are multiples of 9. thus integer
d) 2x is multiple of 9, thus 4*x^2 is multiple of 81. Thus integer
e) 2x is multiple of 9. thus integer/
IMO A
If my post helped you- let me know by pushing the thanks button ;)

Contact me about long distance tutoring!
[email protected]

Cans!!
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 3835
Joined: Fri Apr 02, 2010 10:00 pmFollowed by: 523 members
Location: Milpitas, CA
Thanked: 1854 times
GMAT Score:770

by Anurag@Gurome » Sat Jun 04, 2011 10:12 pm
venmic wrote:If 9 is a factor of 2x then which of the following may not be an integer?

A) 6x/54 + 2x/3
B) (4x-18)/9
C) (2x+27)/9
D) (81-4x²)/81
E) (2x-3)/3
The problem has already been answered but I want to add something.

The critical point for solving this problem is we don't know whether x is integer or not. Usually in this kind of problems the unknown is declared as integer and that may subconsciously lead someone to a false assumption.

If x is integer, then 9 is a factor of 2x means 9 is a factor of x also. But if x is not an integer, then no such conclusion can be made.
Anurag Mairal, Ph.D., MBA
GMAT Expert, Admissions and Career Guidance
Gurome, Inc.
1-800-566-4043 (USA)

Join Our Facebook Groups
GMAT with Gurome
https://www.facebook.com/groups/272466352793633/
Admissions with Gurome
https://www.facebook.com/groups/461459690536574/
Career Advising with Gurome
https://www.facebook.com/groups/360435787349781/
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Master | Next Rank: 500 Posts
Posts: 112
Joined: Sun Jun 13, 2010 9:20 am
Thanked: 5 times
GMAT Score:640

by sunilrawat » Sat Jun 04, 2011 10:28 pm
2x being a miltiple of 9, is also a multiple of 3
a) (3*2x)/(9*6) + 2x/3
Here, the second term is completely divisible by 3 leaving remainder as 0. But in the first term on simplification, we are left with (x/9) which may or may not result in 0 remainder. Thus option A.

Rest all options give 0 remainder and give an integer as the answer on simplification.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Master | Next Rank: 500 Posts
Posts: 126
Joined: Tue Feb 09, 2010 6:37 pmFollowed by: 4 members

by sandeep800 » Sun Jun 05, 2011 10:40 am
IMO A.... Thanx Anurag for additional inputs..
A body of clay, a mind full of play, a moment's life - that is me!!!
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Senior | Next Rank: 100 Posts
Posts: 99
Joined: Sat Oct 16, 2010 1:55 pm
Thanked: 1 times

by aftableo2006 » Sun Jun 05, 2011 11:06 pm
this is a good question a is the answer
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Legendary Member
Posts: 659
Joined: Mon Dec 14, 2009 8:12 amFollowed by: 3 members
Thanked: 32 times

by Gurpinder » Sat Jun 11, 2011 8:46 am
2x/9 = int which also means that 2x is a multiple of 9. Therefore the minimum value of x = 9. So just plug that value in and estimate which answer doesn't workout.

Answer: A

(E) 2(9)-3/3 - since all are multiples of 3, it will workout
(D) since all are multiples of 9, it will workout
(C) since all are multiples of 3 and 9, all will workout
(B) again, all multiples of 3,9--> will workout
(A) This is all you are left with.
"Do not confuse motion and progress. A rocking horse keeps moving but does not make any progress."
- Alfred A. Montapert, Philosopher.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Legendary Member
Posts: 516
Joined: Fri Jul 31, 2009 3:22 pmFollowed by: 13 members
Thanked: 112 times

by smackmartine » Sat Jun 11, 2011 9:16 am
IMO A
As soon as we see there is no restriction on x,we can think of x to be a fraction or integer.
After closely watching each option, we find that all options, but A have a even integer multiplied to it after we solve each expression to its basic form i.e 6x/54 = x/9 .

At x=4.5 , 9 is a factor of 2x.

a)x/9 + 2x/3

2x/3 ---> Integer as 2x is a factor of 9 ,but x/9 =4.5/9 is not.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1